X^2+10x-10=360

Solution for X^2+10x-10=360 equation:

X^2+10X-10=360

We move all terms to the left:

X^2+10X-10-(360)=0

We add all the numbers together, and all the variables

X^2+10X-370=0

a = 1; b = 10; c = -370;
Δ = b2-4ac
Δ = 102-4·1·(-370)
Δ = 1580
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{1580}=\sqrt{4*395}=\sqrt{4}*\sqrt{395}=2\sqrt{395}$
$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(10)-2\sqrt{395}}{2*1}=\frac{-10-2\sqrt{395}}{2}
$
$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(10)+2\sqrt{395}}{2*1}=\frac{-10+2\sqrt{395}}{2}
$